Question

An airplane flies directly above a point on the ground at 1:37 p.m. The airplane is moving at a constant speed of 160 meters/sec. The airplane is also flying at a constant height of 350 meters above the ground. If f denotes the time (in seconds) after 1:37 p.m., express the distance, d, between the point on the ground and the airplane as a function of t.

Answer 1

Since the distance is constantly a changing hypotenuse, the equation would be f(t) = \[\sqrt{25600x ^{2}+122500}\]

Answer 2

Pythagorean theorem.\[D(t)=\sqrt{(160t)^2+350^2}\]

Answer 3

thank you))

Answer 4

Sure :)

Answer 5

No sweat.