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Tricky Probability Question: A bag consists of 1 red marble and 4 green marble. If two marbles are drawn successively without replacement, what is the probability of getting red one??
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why is this tricky?
because two draws one marble
\[1-\frac{4}{5}\times \frac{3}{4}\]
8/20 = 2/5
i get \(\frac 2 5\)
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you solved by calculating the probability of getting green marble
i solved it by calculating the probability of not getting the red one and subtracting the result from 1
tricky answer ... than you
you could also compute \(\frac{1}{5}\times \frac{4}{4}+\frac{4}{5}\times \frac{1}{4}=\frac{1}{5}+\frac{1}{5}=\frac{2}{5}\)
ya that also is
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