Question

How would you prepare 150 mL of a 3.5 M (molarity) of Ca(NO3)2?

Answer 1

to find Molarity i believe you times 3.5 x 2 in Ca and NO3 2X3.5

Answer 2

oh, would that be the answer then? I thought it had to be answered differently because of the whole, "How would you prepare..."

Answer 3

First find the moles in solution.\[.150L \times 3.5M = .525moles\]Then find that amount of moles in grams.\[{164.078 g \over moles} \times .525moles= 86.141g\]So if you put 86.141g of Ca(NO3)2 in 150ml of water you would get a 3.5 molar solution.