Question

in an automotive part manufacturing company, the produced parts are placed in two boxes A and B , it turns that A box contain no deffective part while 1/5 parts in B are defective, a person picks up a box , suppose A and B have equal chance of selection . what is the probability that the person picks up the defective part ?

Answer 1

With these probability problems, I believe you multiply probability by probability to get the final probability. Hopefully these are not homework problems being posted just to get an answer. So how would you start?

Answer 2

Probability of defective part = P(D) = P(D|A)*P(A)+P(D|B)*P(B)
= 0 + 1/5*1/2
=10 %

Answer 3

its not homework i just want to share something , i am studying this right now :P

Answer 4

Correct. 0.5 * 0.2 = 0.1 :)
Ok just making sure :)