Question

find four consecutive even integers such that if the sum of the first and third is multiplied by 2, the result is 20 less than two times fourth.

Answer 1

2x, 2(x+1), 2(x+2), 2(x+3)

2*(2x+2(x+2)) + 20 = 2*2(x+3) find the value of x

Answer 2

http://www.wolframalpha.com/input/?i=2*%282x%2B2%28x%2B2%29%29+%2B+20+%3D+2*2%28x%2B3%29

Answer 3

thank you

Answer 4

yw

Answer 5

the condition of the 1st and 3rd number being a multiple of 2 doesn't need to be considered as the sum of any 2 even numbers is even, and divisible by 2

let the even numbers be

x , x + 2, x + 4 and x + 6

then setting up the equation

x + x+2 + x + 4 + x + 6 = 2(x +6) - 20

gives 4x + 12 = 2x - 8

x = -10

the numbers are

-10, -8, -6, -4