an equation of a circle is given. a. determine its center. b. determine its radius. c. find two points on the circle. x^2 + y^2 = 94

Question

anonymous · Answer

So far, I have a. (x,y) b. approx 9.70 or sq rt 94

experimentx · Answer

center is zero.

experimentx · Answer

your radius is right.

experimentx · Answer

put any value of x less than radius and find r

anonymous · Answer

how did you get 0 for center?

experimentx · Answer

compare with equation standard equation of circle. http://answers.yahoo.com/question/index?qid=20080411074756AAPqBAO

anonymous · Answer

oohh ok

anonymous · Answer

so you plug in a number less than the radius for x? and solve for y?

myininaya · Answer

$$(x-0)^2=x^2 ; (y-0)^2=y^2 $$
So your equation can be written like this:
$$(x-0)^2+(y-0)^2=94$$

experimentx · Answer

yes, it must be less than radius from the center of circle.

myininaya · Answer

$$x,y \in [-\sqrt{94}, \sqrt{94}]$$

anonymous · Answer

I did x=3 and ended up with (3,0) but it's saying 9..

myininaya · Answer

$$x^2+y^2=94$$
If x=3 the we have
$$3^2+y^2=94$$
$$9+y^2=94$$
$$y^2=94-9$$
$$y^2=85$$
$$y=\pm \sqrt{85}$$
$$(3, \sqrt{85}) \text{ and } (3, - \sqrt{85}) \text{ are two points on the circle}$$

anonymous · Answer

oh I was just confused when you put that (x-0)^2 + (y-0)^2 = 94, so I was using that..