Question

problem out of book..
x^(1/2) -3x^(1/4) +2=0

Answer 1

substitute\[u^{2} = \sqrt{x}\]and then you will get a quadratic equation

Answer 2

like
\[x ^{2}-3x+2=0\]?

Answer 3

yes

Answer 4

so then
\[x ^{2}-3x+2+0\]
\[(x-2)(x+1)= 2 and 1?\]the book said the answer was 1 and 16..

Answer 5

\[u^{2} - 3u + 2=0\]\[\left( u - 2 \right)\left( u-1\right)=0\]\[u = 2\]or\[u = 1\]now you can find x by plug in u to the substitution