How would I show that the series: 1 + 1/3 -1/2 +1/5 + 1/7 - 1/4 + 1/9 + 1/11 - 1/6 + ... converges to 3/2 ln 2? (Steps if you wouldn't mind would be helpful in my understanding)
find a rule for the series
might have to split it up into 3 sequences tho
Are you sure that about \[ \frac 3 2 \ln 2\]
\[\sum_{0}^{inf}\frac{1}{2n+1}-\sum_{0}^{inf} \frac{1}{2n+2}\]
Yes I am confused also eliassaab , because I don't think it converges to 3/2 ln 2
@GavinxFiasco at what math class level this question was asked?
http://www.wolframalpha.com/input/?i=sum+%28%284n%2B3%29%282n%2B2%29%2B%284n%2B1%29%282n%2B2%29-%284n%2B1%29%284n%2B3%29%29%2F%28%284n%2B1%29%284n%2B3%29%282n%2B2%29%29+0+to+inf well, it is 3/2 ln(2)
@eliassaab it was asked at first year university level.
One can write the series as \[ \sum_{k=0}^\infty \left( \frac{1}{4 k+1}+\frac{1}{4 k+3}-\frac{1}{2 k+2}\right) = \sum_{k=0}^\infty \left( \frac{8 k+5}{2 (k+1) (4 k+1) (4 k+3)}\right) \] And if you use Wolfram Alpha, you fine that the answer is \[ \frac 32 \ln 2\]
oh thank you this makes alot of sense
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