Question

Can someone please help me with this? I dont need an answer i just need some explanation on how to do it i guess :)
1.
Describe what the graph shows.
https://www.connexus.com/content/media/93289-4142005-104123-AM-1766211605.gif

Answer 1

As the absolute value of slope increases, the velocity (or speed) increase. Should I do it like this?

Answer 2

find the slope, that will be your velocity. you have two different slopes here. so two different velocities. from 0 to 8 be velocity 1 and 8 to 10 be velocity 2. calculate them.

Answer 3

FInd the integral or the area under the curve and you will have total distance.

Answer 4

Callisto speed and velocity are different don't confuse them. The absolute value is speed and without absolute value you get velocity.

Answer 5

Velocity is a vector speed is a magnitude.

Answer 6

To my knowledge, area under this graph is NOT the total distance travelled.
Or it's better for me to amend my answer .
For t=0s - 8s
velocity = (6-9)/(8-0) = -0.375
For t=8 -11s
velocity = (0-6)/(11-8) = -2
Take the absolute value
You'll see the the rate of travelling increases.

Answer 7

Area under the graph is equal to the Integral of velocity, which is displacement/ position. Which will give you the total are equalling total distance.

Answer 8

Please see the axis, it's y=distance , x=time, it's NOT y=velocity , x=time!

Answer 9

in this case velocity is Dx/dt = velocity. In the x direction.

Answer 10

It's the same it's only giving you the distance throughout the total time.

Answer 11

Stop and think. If the line is the rate at which the person is moving. Then the area under the rate is distance.

Answer 12

Perhaps you should read this
http://answers.yahoo.com/question/index?qid=20080906075747AABsnoO

Answer 13

Yes view said article answer under the chosen answer, that guy is correct. It is total distance traveled since there is no negative distance.

Answer 14

Displacement is when you have both negative and positive distances traveled. Please hop off my case bro. I'm too pro.

Answer 15

@UofIMechEng , dont get a bee in your bonnet :)

Noone was "on your case". Callisto was just trying to clarify their postion to avoid confusion.

And yes, area under the velocity curve is displacement - given that we measure it in a straight line right?

Answer 16

Displacement as a straight line yes.

Answer 17

But to answer the question; im not really sure what the graph actually shows :)

it looks to be constant velocities between walking and riding home. Without knowing the route taken, the displacement would seem rather moot to me tho

Answer 18

f(t) = 1/2 t + 9 ; t = [0,8)
= 2t + c ; t = (8,10]

havent the time to determine "c" tho

Answer 19

The graph shows that at time=0 (call this the start time), you are 9 blocks from home. If you look carefully, at time= 3 minutes the graph crosses 8 blocks. That means you are walking 1 block every 3 minutes. At this rate (the slope of the line) it will take you 27 minutes to get home. But at time = 8.5 minutes you get in a car and get home in a total of 11 minutes. Notice that the car is much faster, and the slope of the line is much steeper.

Answer 20

@amistre64 Your equations may confuse Creature. If you magnify the graph you see that the slope is 1/3 on the first line. The 2nd line goes from 8.5 to 11 mins