Question

Sarah, Jim, Lane, David, Chloe and Lisa stand in a row for a family photograph, In how many different ways can they arrange themselves if:

David and Lisa refuse to stand together?

Answer 1

i tried to work it out myself, and i got 4! x 2! x 2! then 6! - this and i ended up with 624, but im not sure if im missing out on anything D:

Answer 2

answer should be
6!-(5!*2!)=480
is it correct??

Answer 3

my way of thinkin is that
no. of reqd permutations is=total permutations - permutations where (D&L stand together )
so you get the no of permutations when they both arent standing together...
total permt=6!(as there are ^ people who can arrange themselves in 6! ways)
permutations where (D&L stand together )=here first consider them as one person -hence total person is 5! and those two can also arrange themselves in 2! ways so hence(5!*2!)
so if my answer is right this is your explanation....

Answer 4

ohhhhhh trueee!! thankyou! :)