Question

if a uniform chain of length "l"slips from a chair nd it1/3part slips frm chair ..can i knw hw much kinetic energy it vill take to slip frm the chair...

Answer 1

poore frasing
please elaborate....

Answer 2

u hv just viewd my quest....u knw the answer...

Answer 3

no iam sorry i do not
i am not even sure i have understood correctly what exactly the question is.
my appologies.

Answer 4

itz out of reach.....u cant understand it...

Answer 5

to be sliping must weirth of hanging chain > friction of rest

Answer 6

if so Velocity mast be calculated dy deferencial equation due to variable to M hanging and friction

Answer 7

IN SOLVING KINETIC ENERGY QUESTION WE MUST HAVE MASS AND THE VELOCITY OF THE BODY. WHAT ARE THEY FROM YOUR QUESTION ?

Answer 8

feel free to help me understand it

Answer 9

ohh srry mass dena bool gaya...mass is
'm
'...nw calculate

Answer 10

nd velocity "v"

Answer 11

BUT if you have been given that the chain is sliping with a steady speed you could calculate the kinetic energy of hanging part

Answer 12

nw i have given all data.....mass,velocita nd length....

Answer 13

is that velocity steady or it only coresponds to time that 1/3 of chain is hanging?

Answer 14

only correspond to tym....

Answer 15

preservation of energy (assuming no friction)
2=all chain hang
1=1/3 of chain hang
K1+U1=K2+U2
1/2 M V1^2 +(-(M/3)*g*(L/6)=1/2 M V2^2+ (-M*g*(L/2)
this should give you final velocity....
i am not sure what :hw much kinetic energy it vill take