Question

mmmmkkkayyy. Slightly bewildered here. (1/2)^-x=1.6... I know this is easier than I am making it,Could someone be so kind to explain this?

Answer 1

\[\left({1 \over 2}\right)^{-x} = \left(\left({1 \over 2}\right)^{-1}\right)^x=2^x\]So we have\[2^x=1.6\]From this, we can take the log base 2 of 1.6 to find x.\[x=\log_2(1.6)\]

Answer 2

To find this, you can calculate\[{\log 1.6 \over \log 2}\]

Answer 3

so if i was to plug that into a calculator I would get the final answer to look something like .678??

Answer 4

That looks correct to me.

Answer 5

Okay Thanks for the help bro!

Answer 6

You're welcome.