Question

http://www.bigideasmath.com/protected/content/ipe_cc/grade%208/extra_help/06/pc_06_q2.html Please help me wit numbers 10, 11 and 13

Answer 1

10. pythagoras laughs at you; sqrt(36+1) = sqrt(37) so ans is c
11. Now Pythagoras is disappointed
13.

Answer 2

10. Pythagoras laughs at you; sqrt(36+1) = sqrt(37) so ans is c
11. 7-2=5, and 3-2=1 so sqrt(25+1) is approximately 5.1 so ans is c
13. \[\huge \sqrt{27^2-20^2}-7=x \]
\[\huge 27=20+7 \] and \[\huge (a+b)^2\ = a^2+2ab+b^2 \]
\[\huge 27^2=(20+7)^2 = 400+280+49 = 729\] BINGO
\[\huge \sqrt{329}-7=x = 11.13835714721705439823\]

Answer 3

So ans is c

Answer 4

ok thx n forget about number 13 and do number 4 at the bottom not at the top

Answer 5

7/5*sqrt(3)