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Mathematics 17 Online
OpenStudy (anonymous):

A particle moves along the x-axis so that its position at any time t> 0 is given by x(t) = t^4 - 10t^3 + 29t^2 - 36t +2. For which value of t is the speed the greatest?

OpenStudy (experimentx):

find maxima

OpenStudy (anonymous):

Maximum at first derivative or second?

OpenStudy (experimentx):

o.. sorry, take derivative ... the resulting function will give you speed.

OpenStudy (experimentx):

and the usual process of maxima

OpenStudy (anonymous):

|dw:1334044638555:dw| The derivative graph looks something like this... where is the maximum?

OpenStudy (experimentx):

do we have any interval of time given??

OpenStudy (anonymous):

No, t>0

OpenStudy (experimentx):

it seems that we have local maximum but's that negative ... I guess at infinity then.

OpenStudy (anonymous):

Lol, but it's multiple choice.. A. t= 1 B. t= 2 C. t= 3 D. t= 4 E. t=5

OpenStudy (experimentx):

the distance is actually decreasing.

OpenStudy (anonymous):

What does that mean for speed? Sorry, I do not understand..

OpenStudy (experimentx):

speed is rate of change of distance ... should always be positive.

OpenStudy (anonymous):

Oh, ok thanks.

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