http://www.ms.uky.edu/~ma123/
Go to Old Exams on the left
Then click Exam 3 with answers from the fall of 2012 (Supposed to say fall 2011 but he made a mistake)

Question

http://www.ms.uky.edu/~ma123/ 
Go to Old Exams on the left
Then click Exam 3 with answers from the fall of 2012 (Supposed to say fall 2011 but he made a mistake)

anonymous · Answer

Why is 13 A NOT C?

anonymous · Answer

@amistre64 
@arcticf0x 
@Callisto 
@jhonyy9 
@KingGeorge 
@LoveYou*69 
@myininaya 
@phi

kinggeorge · Answer

Using the formula on http://en.wikipedia.org/wiki/Trapezoidal_rule we have that the area is about equal to $${1 \over 2}\cdot ((18+23)+(23+24))$$Which equals $${88 \over 2}=44$$

callisto · Answer

Integral = area  under the graph
             = (18+23)*1/2  + (23+24)*1/2
             =44
Note: i divided the area into 2 part, which gives 2 trapeziums

callisto · Answer

*2 parts

kinggeorge · Answer

I just factored out the $1/2$ from Callisto's expression.

callisto · Answer

So, one of the basic concept applied here is that
if you want to find the area under the graph at certain position, just integrate the function from the starting point to the end point you need and vice versa

phi · Answer

It looks like 44 to me

anonymous · Answer

is it always going to be 1/2 or does it depend?

callisto · Answer

It depends
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area of trapezium = 1/2 (a+b) *h

phi · Answer

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