Question

I don't get this integral question? The answer is supposed to be -4 + 20In2 - 6In3, but I keep getting 0

Answer 1

\[2In(u-1)\sqrt{u} - 2\int\limits_{}^{}{u^{1/2}(1/(u-1))}du\] this is what I got so far

Answer 2

\[2\sqrt{n} In(u-1) - 2\left\{ \sqrt{n}In(u-1) - \int\limits_{}^{}In(u-1)(1/2)(u ^{-1/2})du \right\}\]

Answer 3

Then the 2rootIn(u-1) gets cancelled out because there are two of the same terms so I'm just left with the term 2integral(u-1)(1/2).....

Answer 4

Is this right?