The set of integers {3, 4, 5} is a Pythagorean triple. another such set is?
you can multiply each number by any fixed constant if you want another one, say \(\{6,8,10\}\)
but if you want to be more creative and find more that are not multiples of the one you have, there are infinitely many for example \(\{5,12,13\}\)
okay well this question is multiple choice and the answers I have are 6,7,8 6,8,12 6,12,13 and 8,15,17
in fact if you want say 7 to be one side, you can write \[m+n=7,m-n=1\implies m=4,n=3\] and then use \[\{7, 2\times 4\times 3,4^2+3^2\}\] giving the triple \[\{7,24,25\}\]
in that case, your job is not to find one, but to check if \[a^2+b^2=c^2\]
for example \[8^2+15^2=17^2\] \[64+225=289\] which is true the others will be false
ohh okay that makes sense so I just have to check it the pythagorean theorem works
yeah, right
so the answer would be the {8,15,17}
yes, obviously.
thanks so much !
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