Question

What is the sum of all square numbers from 0 to 101?

Answer 1

n(n+1)(2n+1)/6

put n =101.

Answer 2

sum of squares of first 'n' natural or whole nos. is
\[\sum_{i=1}^{n} i^2 = n(n+1)(2n+1)/6\]

so plug in n=101, calculate and enjoy!!

Answer 3

n(n+1)(2n+1)/6

put n =101.

Answer 4

n=101

Answer 5

what you wrote - that's for the first 'n' nos. @KIT3 , not the sum of *square of each no.*