Question

a circle has the equation x^2+y^2=16. find the center, radius and graph

Answer 1

how do I put this in standard form and general form pls?

Answer 2

\[\LARGE (x-0)^2+(y-0)^2=4^2\]
\[\LARGE Q(0,0) \quad r=4\]

Answer 3

(x-a)^2 + (y-b)^2 = r^2

(a,b) = Centre
r = Radius

Centre is (0,0) and
Radius is \[\sqrt{16} = 4\]

Answer 4

thank you ! both of you!

Answer 5

Although this looks like ellipse, is a circle with radius 4 :)

Answer 6

and it is an ellipse, as well as a circle.