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Mathematics 17 Online
OpenStudy (anonymous):

Derivative of e^2x

OpenStudy (anonymous):

2e^2x

OpenStudy (anonymous):

can u explain how u get that is it just using the power rule with the 2

OpenStudy (anonymous):

\[\frac{d}{dx}e^{kx} = ke^{kx}\]

OpenStudy (anonymous):

\[\LARGE (e^u)'=e^u\cdot u'\]

OpenStudy (anonymous):

have you done the chain rule yet?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

so we differentiate e^u and then differentiate u and multiply them together in this case u = kx so du/dx = k

OpenStudy (anonymous):

i dont get it

OpenStudy (anonymous):

which bit confuses you, the chain rule bit?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

ok ill explain it better than i did

OpenStudy (anonymous):

is this how you learnt it? \[\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}\]

OpenStudy (anonymous):

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