A region R is bounded by the curves......
Why are they squared?
Volume = Area*height height = dx Area of circle = \[\huge \pi r^2 \] If you have these concentric circles |dw:1334100348650:dw| and you are interested in the area between them; then the formula is \[\huge \pi R^2-r^2\] Where R is the outer radius or radius of the bigger circle and r is the radius of the smaller circle. First; write y as a function of x \[\huge x(y)=y^{\frac{1}{3}},g(y)=y^2 \] In our case the outer radius is \[\huge x=y^{\frac{1}{3}}\] and the inner radius is \[\huge x=y^2\]the volume revolved about the y-axis would thus be \[\huge \pi\int_0^1{\left(y^{\frac{1}{3}}\right)^2 - \left(y^2 \right)^2}dy\] \[\huge \pi\int_0^1{\left(y^{\frac{2}{3}} - y^4 \right)}dy\] so the answer is actually III
|dw:1334101593857:dw| The smaller radii are generated by the inner function The bigger radii are generated by the outer function.
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