Set up integrals for both orders of integration and use the more convenient order to evaluate the integral over the region R.

R: region bounded by y=0,y=x(squarert), x = 4

y/(1+x^2) dA

Question

Set up integrals for both orders of integration and use the more convenient order to evaluate the integral over the region R. 

R: region bounded by y=0,y=x(squarert), x = 4 

y/(1+x^2) dA

anonymous · Answer

I'm going to retype the eqution

anonymous · Answer

Why dont you set them up >:(

anonymous · Answer

Lol jk

anonymous · Answer

$$\int\limits_{R}^{}\int\limits_{}^{}y/(y/(1+x^2) dA$$

These are the given limits: $$y=0,y=\sqrt{x},x=4$$

anonymous · Answer

opps the numerator should be 1 not y

anonymous · Answer

$$\int\limits_{R}^{}\int\limits_{}^{}y/1+x^2dA$$

anonymous · Answer

Since I'm not given the second x limit, I'm assuming I'll have to graph y=$$\sqrt{x}$$ and x=4

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