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Mathematics 12 Online
OpenStudy (anonymous):

find out the limit of the following ( sin x ) / x where x -> 0

OpenStudy (anonymous):

=1

OpenStudy (anonymous):

plz explain too . i found out it to be 0. u r right it is 1 how

OpenStudy (anonymous):

answer is 1,actually it's proof is a bit theoretical .if you want any proof please refer some standard text

OpenStudy (anonymous):

it's proof is well known and is known as sandwich theorem

OpenStudy (anonymous):

as x reduces, the sin of x also reduces, then why 1

OpenStudy (anonymous):

if u put the value of limit then u will get 0/0 form

OpenStudy (anonymous):

i will get 0

OpenStudy (anonymous):

offcourse buddy

OpenStudy (anonymous):

u can apply dy/dx

OpenStudy (anonymous):

actually 0/0 is a indeterminate value

OpenStudy (anonymous):

derivative ? but i don't know the derivative i'm beginner but soon be older :D :D hahahaa

OpenStudy (anonymous):

this is L hospital rule

OpenStudy (anonymous):

furan.. yah that would be indeterminate state

OpenStudy (anonymous):

ohhh.. hospital ....

OpenStudy (anonymous):

I think the proof starts from some sort of triangle & using some inequality conditions

OpenStudy (anonymous):

buddy L'hospital rule is not the actual prrof

OpenStudy (anonymous):

srry proof

OpenStudy (anonymous):

I KNOW but u also know that proof of this equation is 2 long

OpenStudy (anonymous):

i think for the time being, it is enough that the limit of that is = 1 .... as i will advance in this calculus, i will come across the proof soon and become familiar with that ...

OpenStudy (anonymous):

really too long ? i thought it would be very simple

OpenStudy (anonymous):

okay then you better use L'hospital's rule then

OpenStudy (anonymous):

yah.... i will ... :) thanks all frnds in here .. :) :) :) :) :) :) :) :) :) :) :) :) :) :) :)

OpenStudy (anonymous):

actually sandwich theorem is like the foundation of calculus

OpenStudy (anonymous):

proof is not that long but concept is difficult

OpenStudy (anonymous):

sandwich.... i need to work up at great deal :) :) i will .. bcoz i want to be so perfect in calculus :)

OpenStudy (anonymous):

I remembers the last step

OpenStudy (anonymous):

it's alright no problem. thanks you all alot...... really helpful for me.... :)

OpenStudy (anonymous):

sin(x) for small x is x. x/x is 1 for any x.

OpenStudy (anonymous):

cosx<(sinx/x)<1 here (sinx/x) is sandwiched between cosx & 1 (here not that cosx is also 1 when x tends to zero so sinx/x has no other option other than to tend to zero) that's why it has got the name sandwich or squeeze theorem

OpenStudy (anonymous):

sin(x) / x does not approach 0 in the limit of x -> 0 !!

OpenStudy (anonymous):

you are right cew

OpenStudy (anonymous):

santosh r u there?

OpenStudy (experimentx):

yeah

OpenStudy (anonymous):

hi experimentX, how are you brooo...

OpenStudy (experimentx):

doing fine ... i might be offline pretty soon .. |dw:1334192708048:dw|

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