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find the average value of f(x) = x^2 on the interval [1, 6]
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\[\frac{f(6) -f(1)}{6-1}\]
is it as simple as that? i thought we might have to integrate
how do i do that, please solve it out
surely that answer is finding the average value of a line through 6,f(6) and 1,f(1)
The formula he used is for the mean value theorem, the average value though would be an integral I believe.
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Oh sorry, I found the average rate of change.. My mistake!
In this case we need to use: \[f_{avg} = \frac{1}{6-1}\int\limits_{1}^{6} x^2 dx\]
ok
You are ok from there?
no
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Whats the problem?
i keep getting the wrong answer, i thought it was 7 but its not
Post your steps.
i wrote them out on paper, its fine really
\[\frac{1}{5}*(\frac{6^3}{3}-\frac{1^3}{3})\]
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