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If a chord is perpendicular to a segment drawn from the center of the circle, what do you know about the point where the segment and the chord intersect?
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Midpoint of the chord.
the point is the midpoint of a chord and will result in the segment being perpendicular to the chord
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Theorem: In a circle, a radius perpendicular to a chord bisects the chord. So, the point of interesection of the chord and the radius is the midpoint of the chord.
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You don't need no theorem. Basically, you have an isosceles triangle, and its altitude (perpendicular line from the vertex) bistects the base, in this case the chord.
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