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Mathematics 17 Online
OpenStudy (anonymous):

If a chord is perpendicular to a segment drawn from the center of the circle, what do you know about the point where the segment and the chord intersect?

OpenStudy (anonymous):

Midpoint of the chord.

OpenStudy (campbell_st):

the point is the midpoint of a chord and will result in the segment being perpendicular to the chord

OpenStudy (anonymous):

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Directrix (directrix):

Theorem: In a circle, a radius perpendicular to a chord bisects the chord. So, the point of interesection of the chord and the radius is the midpoint of the chord.

OpenStudy (anonymous):

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OpenStudy (anonymous):

You don't need no theorem. Basically, you have an isosceles triangle, and its altitude (perpendicular line from the vertex) bistects the base, in this case the chord.

OpenStudy (anonymous):

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