A floor has two square-shaped designs. The area of the second square-shaped design is nine times greater than the area of the first square-shaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares? The length of the side of the second square is 9 times greater than the length of the side of the first square. The length of the side of the second square is 6 times greater than the length of the side of the first square. The length of the side of the second square is 3 times greater than the length of the side of the first squar
Lets say the area of one square is 4 . Then that makes the area of the other 36 (Since its 9 times greater) Find the length of the sides . We know that the area of a square is A=s^2 A is already given so we take the square root of the areas to find the length of one side sqrt 4 = 2 sqrt 36= 6 How many times is greater is 6 compared to 2?
wait no 3 times
yep :D
thanks
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