Question

Solve for x.
Log[6] (5x+2) - log [6] (x-1) = log [6] (x-2)

Answer 1

\[\LARGE \log_{6}(5x+2)-\log_6(x-1)=\log_6(x-2)\] this ?

Answer 2

yes

Answer 3

\[\log(a)-\log(b)=\log(\frac{a}{b})\] so start with
\[\log(\frac{5x+2}{x-1})=\log(x-2)\] and therefore
\[\frac{5x+2}{x-1}=x-2\]

Answer 4

hah.. go satellite, your turn :F

Answer 5

How exactly do I solve for x ?

Answer 6

start from the last fraction satellite left for you... just use cross multiply and do the necessary simplification\multiply and you should find x... still having doubts ? :O

Answer 7

A little bit. I don't want you guys to give me the answer but can you elaborate more or do a similar problem?

Answer 8

\[\frac{5x+2}{x-1}=x-2\]
\[5x+2=(x-2)(x-1)\]
\[5x+2=x^2-3x+1\] now you have a quadratic equation to solve

Answer 9

the answer is x=8

Answer 10

ay... okay . thanks i got it from here.