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Mathematics 25 Online
OpenStudy (anonymous):

prove : if f(x) is differentiable at x, then f(x) is continuous at x or vice versa

OpenStudy (experimentx):

Differentiability implies continuity But continuity doesn't necessarily imply differentiability

OpenStudy (anonymous):

...still, how to prove it?

OpenStudy (experimentx):

If a function f(x) is differentiable on x = a then the term lim x->a (f(x) - f(a)) / (x-a) is well defined. then lim x->a (f(x) - f(a)) = lim x->a (x-a) (f(x) - f(a))/(x-a) =lim x->a (x-a) lim x->a (f(x) - f(a))/(x-a) = 0 * f'(a) = 0 lim x->a (f(x) - f(a)) = 0 => lim x->a (f(x) = f(a)) (which implies continuity) But reverse may not apply, for example f(x) = |x| is not differentiable at x=0 though continuous

OpenStudy (experimentx):

the other example would be x sin(1/x) at x = 0 http://en.wikipedia.org/wiki/Weierstrass_function

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