If you have 410 grams of propane(C3H8) and want to know how many grams of oxygen are required to burn it. Find the number of moles of propane that you have. Convert grams to moles!

btw, the balanced equation for the combustion of propane is :
C3H8 + 5O2 3CO2 + 4H20

Question

If you have 410 grams of propane(C3H8) and want to know how many grams of oxygen are required to burn it. Find the number of moles of propane that you have. Convert grams to moles!

btw, the balanced equation for the combustion of propane is : 
 C3H8 + 5O2 > 3CO2 + 4H20

mos1635 · Answer

no of moles=mass/molucule mass=410/44
C3H8        +    5O2     -> 3CO2 + 4H20
1 mole  requirs 5 mole
410/44            x=?
do the math

anonymous · Answer

What mos 1635 means is multiply the number of moles of propane (410/44) by 5 (ie every propane molecule needs 5 oxygen molecules). Then multiply the answer by 32 because each oxygen molecule is 32 Daltons (on average) so each mole of oxygen is 32g.