Question

(-mn^8)^2

Answer 1

(-mn^8)(-mn^8)

Answer 2

does that help?

Answer 3

not really

Answer 4

(-mn^8)(-mn^8)
=
m^(2)n^(16)

Answer 5

\[(-n)^2(m^8)^2\]
\[n^2m^{16}\]

Answer 6

you add expoents when multiplying like variables

Answer 7

(-mn^8)(-mn^8) = mn^16

Answer 8

and (-)(+) = -, (-)(-) = +, (+)(+) = +

Answer 9

Exponent 2 on the m, my mad, missed that.

Answer 10

petewe that is wrong you forgot to multiply m^(1)m^(1) = m^(2)

Answer 11

Yep.

Answer 12

yall confusing me

Answer 13

do you understand that
(-mn^8)^2 = (-mn^(8))(-mn^(8))

Answer 14

x^(2) = (x)(x)
x^(3) = (x)(x)(x)

(1 + y)^(2) = (1+y)(1+y)
(1 + y)^(3) = (1+y)(1+y)(1+y)
etc...

Answer 15

yes understand that but i dont understand how you put themt ogether

Answer 16

well if we multiply them it just becomes
(remember the negatives cancel out)
mn^(8)mn^(8

Answer 17

then you can just add the exponents of like variables

Answer 18

so m^2n^2 ^16?

i dnt understand

Answer 19

Go step by step. Multiply the m's first. (-m)(-m) = m^2 and (n^8)(n^8) = n^16
Recall your exponent laws. When multiplying exponents of the same base, add the exponents.

Does that make it easier?

Answer 20

somewhat

Answer 21

Put it together, you get m^2n^16)

Answer 22

m^(8)m^(8)n^(1)n^(1)
for m 8+8 = 16
for n 1 + 1 = 2

thus you have m^(16)n^(2)

remember anything can be raised to the power of 1 and is raised to the power of 1

5^(1) = 5
x^(1) = x
6^(1) = 6
etc

Answer 23

okay i get it now