How many solutions does Cos^-1(0) have? My answer is 1...is this correct?
Yeah you're right
\[ \frac \pi2 \] if you mean the one valued function \[ \cos^{-1}(0) \]
1 is not right.
@eliassaab , is that how many solutions Cos^-1(0) can have? Or something else?
If \[y = \cos^{-1} 0\] then there is one solution for y but if we have \[ \cos y=0\] and we need to find the solution of this then there are innumerable solutions
Yeah it's how many solutions there are for the entire notation Cos^-1(0)...so it's infinite?
@missfitz5172 you're correct. It has only 1 solution because \[ \cos^{-1} x\] is defined like that its range is [0, \(\pi\)] so only one solution exist at \(\pi/2\)
@ash2326 oh ok that makes sense! thank you very much!
You got it??
yeah! (:
Welcome to Open Study:) Glad to help you:D
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