Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Can you help me here please?

OpenStudy (anonymous):

OpenStudy (callisto):

For (a), what do you think?

OpenStudy (anonymous):

Ok

OpenStudy (callisto):

Nah?

OpenStudy (anonymous):

nah? What do you mean?

OpenStudy (callisto):

Hmm... nothing, sorry, what do you think for (a)?

OpenStudy (anonymous):

For this, Should I find the reference angle?

OpenStudy (callisto):

Hmm, for these kind of question, you need to consider angle in each quadrant. I mean which quadrant(s) give(s) you a negative value for sine ratio

OpenStudy (anonymous):

Quadrant 3 and 4

OpenStudy (callisto):

So, how many possible value for theta?

OpenStudy (anonymous):

2 right?

OpenStudy (callisto):

yes :)

OpenStudy (callisto):

and you've also got the answer for (b), do you know why?

OpenStudy (anonymous):

because the solutions lie in q3 and q4

OpenStudy (anonymous):

How do I explain answer a though? Like I get why it would be 2solutions but is there a better explanation?

OpenStudy (anonymous):

@DhananjayMaurya, Thank you for the medal:)

OpenStudy (callisto):

because there are 2 quadrants give negative values for sine ratio, so there are 2 solutions :P Not sure if this is correct

OpenStudy (anonymous):

Ok, that kind of makes sense:). For question 3,is the reference angle by any chance -0.4468?

OpenStudy (callisto):

if -1≦sin theta ≦1 , then it is possible

OpenStudy (anonymous):

What formula would I normally use to find the reference angle? I forget

OpenStudy (callisto):

sin theta = sth theta = sin^-1 sth

OpenStudy (anonymous):

yeah. Thats what i put. Sin-1 (-0.4321) So reference angle -0.4468 is correct right>?

OpenStudy (callisto):

nope.. sin^-1 is arc sin

OpenStudy (anonymous):

Ok, so my reference angle is 25.60 degrees right?

OpenStudy (callisto):

25.60 is in quadrant I, you need the angle in quadrant III and IV~

OpenStudy (anonymous):

I would make it -25 but isnt reference angle always the absolute value?

OpenStudy (callisto):

-25.60 = 360-25.60 = angle in quadrant IV :)

OpenStudy (anonymous):

so reference angle is not +25 but -25?

OpenStudy (callisto):

One of the reference angle is 360-25.60

OpenStudy (anonymous):

And the two possible solutions are theta1 = 180 + 25.6 = 205.6 degrees theta2 = 360-25.6 = 334.4 degrees

OpenStudy (anonymous):

right?

OpenStudy (callisto):

Yup~~~

OpenStudy (anonymous):

Thank you. Sorry to bother you, Im sure youre busy. Thank you:)

OpenStudy (callisto):

I'm sorry.... really sorry that I didn't respond right after you had!!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!