1. Given 5 people. a) 3 people are selected randomly, how many possible combination? (b) 3 people are selected randomly to form leader team of three(president, vice president, and secretary).How many possible leader teams?. (c) What is the probability that one particular person becomes the president?
a) 5*4*3
Okay no. of ways of selecting three things out of 5 is "5C3". thats for (a)
Yeah got that
So what about b?
now in the second part, you are basically selecting three people and them arranging them. (like putting labels of president, VP and secretary on their heads. how many ways do you do that?) so that is permutation. so here 5P3
But isn't it how many possible leader teams ?
how many possible leader teams => 3P3 = 3x2x1 =6
oops i didnt read that last part "how many possible leader teams". *face palm* one sec
This is the kind of math that @Mimi_x3 glances at with blank stares.
This is the topic that makes me hyper-ventilate as well. :/
lol
Now C :D
okay i ll forget the rules and go by the basics hmm, so how many possible leader teams. so what happens is that first we find the no. of ways of selecting the 3-member bozos team. that we did in part "a". and then no. of ways of arranging them in their posts. so 5C3 * 3 * 2 which is the same as 5P3
it snot how many team leaders. its how many possible teams with different configuration of bozos at doff level.. Now "C"
a) the possible combination=\[5C3\] b)5p3..here will be arrangement . c)1/5
No wait shouldn't it be 3P3 why is it 5C3*3*2 ?
probability of selecting a president= probability of choosing him from the bunch into the leader team x probability that he is given the presidential seat. = 1/5 x 1/3=1/15 thats what i think. i may be wrong
@apoorvk ...here any person may be a president among 5 persons.
i think so. its 5P3 because. first you must select the group of 3 bozos. after that you 'll assign them posts isnt it? making that executive body has some no. of ways. then the no. of ways that the team may be assigned posts. if its already provided that a group of three has been selected, then yes ofcourse among those three can the team arrangements be made, and then only its 3P3
@taufique think this over. yes any one of the 5 may be the president, but first the guy has to be selected into the elite panel, right? so there is probability of that (1 out of 5). (cause he may or may not be selected into that panel). then, when in the panel, he may be a president or not (1 out of 3).
@diya clear hai? ya aur sprite pilaaoon? =]
@apoorvk the three persons has been selected from 5 persons.
Hmm okayy !! Got it!! Thankssss @apoorvk I'll think about second one lol
Its never been mentioned that 3 people have been already selected @taufique . read again diya, yeah do that. pondering over it will help you get clear (why 3P3 or 5P3). or if you have an answer in the book, post that.
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