Plane geometry question #1 - centres in a triangle
Very easy.
Find the distances first using distance formula.
\[ \left(\frac{ (ax_1+bx_2+cx_3)}{(a+b+c)}, \frac{ (ay_1+by_2+cy_3)}{(a+b+c)} \right) \]
So... what do you get for the answer?
I have to do it ? lol
nope, I realised that I got it correct actually :S
(2,2) btw this is a Equilateral triangle so you can just find the centroid.
o.o .................................... Are you sure.......................?
2,2 is not the answer?
The answer is not (2,2) ............ ( Shocked!!!!!)
OOPS this is not a equilateral triangle. We have the use the in-center formula here.
in-center formula? Never heard of it !
It's elementary. How did you solved it?
Distance formula, I supposed. Did it few months ago, not sure.
I supposed this time I need to google it myself, nevermind
\[\frac{6*6}{6 + 6 + \sqrt2 6} = \frac{6}{2 + \sqrt2} = \frac{6(2-\sqrt2)}2 = 3(2 - \sqrt2)\]
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