Coordination Geometry question #2 - circle
I and II.
if need explain tell me
Sorry, but if the answer is correct, then yours would be wrong...
ups, you right i did for x axis, my bad
answer would be II adn III
If I give a random answer can I still get a medal :p
Seems you've got what you want...
need explain, if no say so. TuringTest is hunting me...:) for answers with no explain
@myko the way you get the answer is my concern!!!
lolols I wasn't serious hahaha that is too much for meh ...your problem is
@myko lol don't worry, I would do the hunting job myself first :)
Perhaps just explain one of the cases. I would try for the rest. I don't want to be fed with the solution only :)
Substitute x=0 in each equation. If you get a real value for y, then the circle intersects the y-axis, otherwise not. (RRemember that k<h)
ok, here it goes... the equation of the circle in the for it's given is telling you the center of it and it's radius. ( x-h)2 +(y-k)2 = r2 Center would be (h,k) and radius sqrt(r) So you see, the circle is moved to point (h,k) with radius sqrt(r) so if radius is less than k it won't touch the y axis
where i wrote sqrt(r) should say sqrt(r2)
@Mani_Jha Thanks for the hints, I got it by checking delta :) @myko don't really understand your method :S
My method is the most simple one you can imagin @Callisto
@myko, I think you're checking whether the circle touches(that means, whether y-axis is a tangent) the y-axis. But the question just asks for intersection, and for that there's no necessity of a tangent.
@myko How did you determine that I is not the answer?
i just check if the distance that the center of the circle is moved from y axis is more, less or equal to it's radius @Mani_Jha
if it's tangent is also valid @Mani_Jha
@myko what about my question.... /____\ ???
I is not the answer becouse it says that k<h and the (x-h) term says that this distance is more than k. So it won't reach the y axis
|dw:1334328583388:dw|
|dw:1334328675660:dw| wrong quadrant, sry. But the idea is still the same
Join our real-time social learning platform and learn together with your friends!