Question

Determine the number & type of solutions for x^2+4x+3=0
a) 1 rational double
b) 2 irrational
c) 2 rational
d) 2 complex
Someone please help me

Answer 1

Try solving it using the quadratic formula -b +or- squareroot( b^2 - 4ac) / 2a

Answer 2

where a =1 b =4 and c=3 in this case.

Answer 3

Or you can simplify x^2+4x+3
x^2+4x+3= (x + 1)(x + 3)

Answer 4

in this case you can see that x will equal -3 and -1.

Answer 5

I basically solved it for you :/ all you have to do is figure out if -3 and -1 are rational, irrational or complex

Answer 6

for a quadratic equation, as Romero says, we have a formula

the important bit for evaluating the type of root is called the "discriminant"

its the bit in the square root
if \[ax^2 + bx + c =0\]
the discriminant is
\[\Delta = b^2 - 4ac\]
if
\[\Delta = n^2\]
where n is an integer we get rational roots

if
\[\Delta < 0\]

we have complex roots

if
\[\Delta = 0\]
we have repeated roots

etc etc

Answer 7

they are rational, right?

Answer 8

Yes, they are rational numbers.

Answer 9

thank you everyone.