Question

Differentiate the function g(x) = ln [x*sqrt(x^2 - 1)]

Answer 1

\[g(x) = \ln (x \sqrt(x^2 - 1))\]
this one?

Answer 2

use chain rule

Answer 3

start with
\[\ln(x)+\frac{1}{2}\ln(x+1)+\frac{1}{2}\ln(x-1)\] and it will be easier

Answer 4

sooo g'(x) = 1/x + 1/x(x+1) + 1/x(x-1) ?

Answer 5

stupid i know but i'm having trouble simplifying that what do i do

Answer 6

g'(x) = 1/x + 1/2(1/(x+1)) + 1/2(1/(x-1))
= 1/x + 1/2(x+1) + 1/2(x-1)

Answer 7

well yeah i got that sorry i typed it wrong but i need to simplify that