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Mathematics 12 Online
OpenStudy (anonymous):

Find ∫sin (πx/2)

OpenStudy (amistre64):

what does sin integrate to?

OpenStudy (anonymous):

-cos

OpenStudy (amistre64):

then we know this at least has to come from -cos(pi x/2) taket he derivative of that to see what we need to include.

OpenStudy (anonymous):

Theres my problem we get sin(pix/2) times (pi/2)

OpenStudy (anonymous):

So I need something that cancles out the (pi/2)

OpenStudy (amistre64):

then we need to find a pi/2 to attach to our integral so that we have exactly that :)

OpenStudy (amistre64):

does 2/pi cancel out pi/2?

OpenStudy (anonymous):

Yeah

OpenStudy (amistre64):

then lets us that :)

OpenStudy (amistre64):

\[\frac{d}{dx}[-\frac{2}{pi}cos(\frac{pi}{2}x)]\to\ \frac{2pi}{2pi}sin(\frac{pi}{2}x)\]

OpenStudy (anonymous):

Thank you, I have to admit that was fun

OpenStudy (amistre64):

lol :)

OpenStudy (amistre64):

when the problems arent so basic, they use something called a u-sub technique to clean things up

OpenStudy (amistre64):

\[\int sin(pix/2)dx\] \[pix/2 = u\] \[\frac{d}{dx}[pix/2 = u]\to\ \frac{dx}{dx}pi/2 = \frac{du}{dx}\] \[dx=\frac{2}{pi}du\] substitute the parts now \[\int sin(pix/2)dx\]\[\int sin(u)\frac{2}{pi}du\to\ \frac{2}{pi} \int sin(u)du\]

OpenStudy (anonymous):

o ok I didnt think to use the u sub when I was looking at it

OpenStudy (amistre64):

i did, but felt it rather pointless :) when they are this basic, you need to develop a foresight

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