Question

The equation of a line that goes through the points (5,9) and(6,3) can be written in the form y=mx+b. Where is m? Where is b?

Answer 1

You should first make that equation into the slope intercept form
y=mx+b
-5x+3y+6=0
3y=5x-6
Divide everything by 3
What would be the new equation?

Answer 2

Dude your slope is 5/3
Just express that in decimal

Answer 3

Have you tried inputting 1.67? because I think it won't accept 1.666666667....

Answer 4

Ok for the new question use the slope-point formula

y-y1= m(x-x1)

y-3=4(x-7)
y-3 =4x-28
y=4x-25
m=4
b=-25

Answer 5

use the slope-point formula (again :)) )
m=-2
P(6,-4)

y-y1= m(x-x1)

y+4=-2(x-6)
y+4 =-2x+12
y=-2x+8
m=-2
b=8

Answer 6

You know it would be better if you post your questions individually instead of editing so everyone can see it easier

Answer 7

find the gradient( slope). Its rise/run

\[m = (y _{2} - y _{1})/(x _{2} - x _{1})\]

in your question use (6,3) as the 2 point and (5, 9) as the 1 point

then \[m = (3 - 9)/(6 - 5)\]

the gradient(slope) of the line is -6

next use the point gradient formula to find the equation of the line

\[y - y _{1} = m( x - x _{1})\]

using m = -6 and the point ( (5, 9)

y - 9 = -6(x - 5)

expand and simplify

y = -6x + 39