Question

(x−5)^9(x−2)^4(x+10)^8

urggg this is really frustrating, someone post solution please

Answer 1

where is the function increasing

Answer 2

woah this is a scary one but you can figure this out by using the powers ... i just don't remember off the top of my head how that works lol

Answer 3

you know the x-intercepts so you just have to figure out how even functions and odd functions work

Answer 4

you take the first derivative; its just the product rule

Answer 5

the zeros remain the same for the derivative; 5, 2, and -10

Answer 6

then use an advantageous number inbetween them to test for sign

Answer 7

i tested them and they are increasing on every interval. how do i write that in interval notation

Answer 8

Increase : \[(-\infty,\infty)\]?

Answer 9

if its increasing everywhere except where it zeros; you want to Union up the intersections

Answer 10

(-inf,a)U(a,b)U(b,inf)

Answer 11

http://www.wolframalpha.com/input/?i=y%3D%28x%E2%88%925%29%5E9%28x%E2%88%922%29%5E4%28x%2B10%29%5E8

you might wanna rechk your interval

Answer 12

(-inf,-10)U(2,5)U(5,inf) ???

Answer 13

that would be it if your pos/neg was accurate

Answer 14

is it not? can you check pls?

Answer 15

(x−5)^9(x−2)^4(x+10)^8

9(x−5)^8 (x−2)^4 (x+10)^8+ (x−5)^9 4(x−2)^3 (x+10)^8 + (x−5)^9 (x−2)^4 8(x+10)^7

wolfram would be simpler

Answer 16

for the first interval (-inf, -10)
9(-11−5)^8 (-11−2)^4
= 1104

Answer 17

thats interval is + yes

but i keep getting something wierd around x=-5

Answer 18

your inputing that into f(x); f'(x) defines the slope; and whenever the slope is positive we are increasing

Answer 19

am i using the derivative or the original equation to determine where the slope is increasing?

Answer 20

the derivative defines slope; slope tells us increase or decrese

Answer 21

ive zoomed in at 5 points; x=-10,-4.75,2,3,5 these seem to be zeros