Question

how do i solve (1-i)^6

Answer 1

ıs i complex number?

Answer 2

dude ,dont take the pervious answer it was wrong ,ma small brother fault !!!

Answer 3

first change it into e^itheta form

Answer 4

|1-i| <--- first find the mod => \( \sqrt{1^+(-1)^2} = \sqrt2\)

=> \( \sqrt2 ( \frac{1}{\sqrt 2} - \frac{1}{\sqrt 2} i )\)
=> \( \sqrt2 ( \cos (-\pi/4) + \sin (-\pi/4) i)\)
=> \( \sqrt2 ( e^{-i\pi/4})\)

Now it should be easy.

Answer 5

The answer I got was 8i after inserting your equation into a calculator.

Answer 6

http://www.wolframalpha.com/input/?i=%281-i%29%5E6