Calculate the complex zeros. x^3-6.86486x^2-12.65743718x-44.02540042 How would you go about doing that? Since you can't use quadratic..
are you really supposed to be able to solve this without a computer?
ummm u use quadratic formula. Like i programmed a program on my calc so like its easy
Well I got that after I did synthetic division, that's what it says in the steps my teach gave me, but I can't use quadratic to find the complex zeros because it's not x^2. And we have to show our work.
ohhh i didnt see the x^3
I had to use a complicated equation...grrrrr
the only easy way to find complex roots is with the quadratic formula (for quadratics of course) since it's decimal coefficients it'll be crazy to look for another real zero I really can't see any way around using a computer
What was the original question?
There was a way but it's is no where near easy.
Calculate the complex zeros in x^3-6.86486x^2-12.65743718x-44.02540042..can't use quadratic..have to show work
Well I'm all for it if it will get this done
Oh man, c'mon FFM this ought to be interesting I assume you'll just give us a link
Cardano's method: http://en.wikipedia.org/wiki/Cubic_function#Cardano.27s_method We have this in our undergrad syllabus. But note I have never applied it on something looking this horrible.
I believe the Lagrange's method is somewhat more convulsive and advance.
Holy crap...yeah she can deal with me using a computer and just putting down that's what I did...
Lol, Good luck!
Thanks!
oh yeah, I forgot about that thing ugy
ugly*
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