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Mathematics 15 Online
OpenStudy (anonymous):

Calculate the complex zeros. x^3-6.86486x^2-12.65743718x-44.02540042 How would you go about doing that? Since you can't use quadratic..

OpenStudy (turingtest):

are you really supposed to be able to solve this without a computer?

OpenStudy (anonymous):

ummm u use quadratic formula. Like i programmed a program on my calc so like its easy

OpenStudy (anonymous):

Well I got that after I did synthetic division, that's what it says in the steps my teach gave me, but I can't use quadratic to find the complex zeros because it's not x^2. And we have to show our work.

OpenStudy (anonymous):

ohhh i didnt see the x^3

OpenStudy (anonymous):

I had to use a complicated equation...grrrrr

OpenStudy (turingtest):

the only easy way to find complex roots is with the quadratic formula (for quadratics of course) since it's decimal coefficients it'll be crazy to look for another real zero I really can't see any way around using a computer

OpenStudy (anonymous):

What was the original question?

OpenStudy (anonymous):

There was a way but it's is no where near easy.

OpenStudy (anonymous):

Calculate the complex zeros in x^3-6.86486x^2-12.65743718x-44.02540042..can't use quadratic..have to show work

OpenStudy (anonymous):

Well I'm all for it if it will get this done

OpenStudy (turingtest):

Oh man, c'mon FFM this ought to be interesting I assume you'll just give us a link

OpenStudy (anonymous):

Cardano's method: http://en.wikipedia.org/wiki/Cubic_function#Cardano.27s_method We have this in our undergrad syllabus. But note I have never applied it on something looking this horrible.

OpenStudy (anonymous):

I believe the Lagrange's method is somewhat more convulsive and advance.

OpenStudy (anonymous):

Holy crap...yeah she can deal with me using a computer and just putting down that's what I did...

OpenStudy (anonymous):

Lol, Good luck!

OpenStudy (anonymous):

Thanks!

OpenStudy (turingtest):

oh yeah, I forgot about that thing ugy

OpenStudy (turingtest):

ugly*

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