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Chemistry 11 Online
OpenStudy (anonymous):

q=mcAT question: If 0.4kj of heat is removed from a sample of water and it cools from 25 degrees Celsius to 15 degrees Celsius, what is the mass of the water? I keep getting 0.01, but I know the answer is 10 - help?

OpenStudy (anonymous):

the answer depends on the units.. its 0.01kg or 10g..

OpenStudy (anonymous):

both kg and g are units of mass, what value you end up with will depend on the units of your c and then you can convert to whatever you want

OpenStudy (anonymous):

We haven't gotten up to kg yet, it's still the first lesson, so I assume were sticking to g.

OpenStudy (anonymous):

Main point is: Do you know where I went wrong?

OpenStudy (anonymous):

I'm happy to provide work.

OpenStudy (anonymous):

you didn't go wrong... you have to always include the units when you are solving problems.. do you know what the units are for the value of 4 that you posted?

OpenStudy (anonymous):

g

OpenStudy (anonymous):

It was actually 4.18, but we had to round to the nearest sig fig.

OpenStudy (anonymous):

the value of c ~ 4 kJ / (kg * C)

OpenStudy (anonymous):

But isn't that the formula for raising heat 1 degree higher? Shouldn't I use the mcAT form.?

OpenStudy (anonymous):

*confused

OpenStudy (anonymous):

yes you will use the q = mcat equation... can you rearrange that formula to determine the mass? m = what?

OpenStudy (anonymous):

m= q/cAT ?

OpenStudy (anonymous):

yes that's correct.. now fill in the variables while including the units.. which is what you did before as well

OpenStudy (anonymous):

(0.4 kJ)/ (4 kJ/ (kg * degree c) * 10 degrees C)

OpenStudy (anonymous):

so just note that whatever you get.. the answer will be in kilograms... and there are 1000 grams in 1 kilogram.. so you can convert to get the answer in grams

OpenStudy (anonymous):

are you sure that makes sense?

OpenStudy (anonymous):

Yup, my work was all over the place. Plus I didn't change the formula for mass like you did - I'll be sure to use that next time.

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