q=mcAT question: If 0.4kj of heat is removed from a sample of water and it cools from 25 degrees Celsius to 15 degrees Celsius, what is the mass of the water? I keep getting 0.01, but I know the answer is 10 - help?
the answer depends on the units.. its 0.01kg or 10g..
both kg and g are units of mass, what value you end up with will depend on the units of your c and then you can convert to whatever you want
We haven't gotten up to kg yet, it's still the first lesson, so I assume were sticking to g.
Main point is: Do you know where I went wrong?
I'm happy to provide work.
you didn't go wrong... you have to always include the units when you are solving problems.. do you know what the units are for the value of 4 that you posted?
g
It was actually 4.18, but we had to round to the nearest sig fig.
the value of c ~ 4 kJ / (kg * C)
But isn't that the formula for raising heat 1 degree higher? Shouldn't I use the mcAT form.?
*confused
yes you will use the q = mcat equation... can you rearrange that formula to determine the mass? m = what?
m= q/cAT ?
yes that's correct.. now fill in the variables while including the units.. which is what you did before as well
(0.4 kJ)/ (4 kJ/ (kg * degree c) * 10 degrees C)
so just note that whatever you get.. the answer will be in kilograms... and there are 1000 grams in 1 kilogram.. so you can convert to get the answer in grams
are you sure that makes sense?
Yup, my work was all over the place. Plus I didn't change the formula for mass like you did - I'll be sure to use that next time.
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