Question

I've been stumped on this problem forever. I've been trying to answer but no luck, I just don't understand it.
http://imageshack.us/photo/my-images/822/questionc.jpg/
How do I go about figuring it out?

Answer 1

Add values and calculate? Its common knowledge for me, but if you don't figure it out yourself, it won't sponge on your brain.

Answer 2

Add values? They're arbitrary numbers, what am I supposed to calculate?

Answer 3

current coming out of battery will be the some of that passing through each bulb...since each bulb is aatached to commen batery they will have same potential diff across them...to decrease current we can just try to decrease current through any bulb...V=IR..
V=fixed..so I is proportional to 1/R...so increse resistance of any bulb and current will decrease..hence (b,d,g)...it is obvious that a low voltage battery will give low current if resistance remains same hence (f) so ans is (b,d,f,g)

Answer 4

Add resistance values. Add a voltage value. Make something up. And use the formulae @quarkine gave.

Answer 5

That's how I found out. I WiSh someone came along and dropped the ans on me like that.

Answer 6

hey its 'sum' not 'some' in 1st line..i guess tying is affected when u r simultaneously tryin to see a movie ;)

Answer 7

name R1,R2,R3 each resistanse
aplay ohm low for each bulb (note: same V)
aplay kirchoff 1st low for sirquit
check each of given changes what resalt they have

Answer 8

bingo^