Question

!@#$%%anyone can explain to me how to do this??

Answer 1

a)bottom left

Answer 2

you need to identify the amplitude of the curve which in this case is 36

the + 14 is the centre of the curve.

the the curve moves between 14 + 36 = 50 and 14 - 36 = -22

you need to find the value of t that gives the temperature of -22... the lowest point on the curve

so you have

-22 = 36sin(2pi/365(t-101)) + 14

subtract 14

- 36 = 36sin(2pi/365(t-101))

divide by 36

-1 = sin(2pi/365(t-101))

use arcsin or sin^-1

\[\sin^{-1} =3pi/2\]

then

3pi/2 = 2pi/365(t-101)

multiply by 365 and divide by 2pi

gives t - 101 = 273.75

t = 374.75 ot 375

which is 365 + 10

so the 10th day

Answer 3

when t=0
T=-21.5 degrees