Row reduce the augment matrix [A 0] to echelon form where...
A=\[\left[\begin{matrix}-3 & 6 & -1 & 1 & -7\\ 1 & -2 & 2 & 3 & -1\\ 2 & -4 & 5 & 8 & -4\end{matrix}\right]\]
My book didn't do any steps and gives me a matrix where the whole bottom row is zero. I really don't see how the book got to that.
The procedure is simple. It says use raw operations, so you have to change using: raw switch place, raw multiplication by number, raw adition; make you matrix look similar like :upper triangular matrix. It means all the elements that are under the mane diagonal are 0 and the numbers on the pivots are all 1
Yes I tried doing that right fromt he start I don't see how one row completely turns into zero since none of the rows are scalar multiples of each other.
Oh nevermind ima try to redo it see if it comes out right.
first put 2º raw up
Kk I got it. Can you tell me what the free variables are?
if it says that the matrix is augmented it means it is a 3x4 matrix. so there are 4 variables. since you say that the last raw is all 0, it means that onle 2 raws are independent. So 2 of 4 variables are free
I actually got 3 " X2 X4 X5 I was just checking if these are right
its a 3 X 5btw
hmm augmented matrix means that the right hand side of the equality is included in the matrix. ...
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