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-4-3i ---------- 2-i
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multiply top and bottom by the conjugate of the denominator, which is \(2+i\)
this always works because \((a+bi)(a-bi)=a^2+b^2\) a real number
@satellite73 , omg! you are back at 99. :O
ikr wtp?
i had over ten thousand medals, countless hours and answers. now i am no longer a legend, just a guru. jesus
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i need help!
satellite..how do you do latex in line with the text? might i ask? @lunsfordc11 like @satellite73 said..multiply the numerator and denomiator by 2+i to get a difference of two squares which is (2^2 - i^2)
i didn't get that answer. it will be nice to get help step by step
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