how do you evaluate the indefinite integral: x^4 √2+x^5 dx ??
let √2+x^5 = u
and then what do you do with x^4?
du = 5x^4 dx
1/5 (5x^4 dx)/ (sqrt(2)+x^5) 1/5 du/u
is 1/5 du/u the answer ?
no integrate it ... i think you know how to integrate it.
wher yu get 1/5 from?
(5x^4 dx)/5(sqrt(2)+x^5) multiplied both top and bottom.
1/5 5x^5/5 / 2x^5/4 + c, is that correct?
no ... you did not integrate your answer will be 1/5 ln ( sqrt(2) + x^5) + C <--- try checking on wolfram.
whats the answer though ?
http://www.wolframalpha.com/input/?i=integrate++x%5E4%2F%28+%E2%88%9A2%2Bx%5E5%29+dx Click on ... show steps to view the steps.
Well, what do you need help with? Looks, like someone answered it..
i still dont know the answer!
The link gives you the answer.. or you don't know how to do it?
oh thanks!
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