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OpenStudy (anonymous):
how do you evaluate the indefinite integral: x^4 √2+x^5 dx ??
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OpenStudy (experimentx):
let √2+x^5 = u
OpenStudy (anonymous):
and then what do you do with x^4?
OpenStudy (experimentx):
du = 5x^4 dx
OpenStudy (experimentx):
1/5 (5x^4 dx)/ (sqrt(2)+x^5)
1/5 du/u
OpenStudy (anonymous):
is 1/5 du/u the answer ?
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OpenStudy (experimentx):
no integrate it ... i think you know how to integrate it.
OpenStudy (anonymous):
wher yu get 1/5 from?
OpenStudy (experimentx):
(5x^4 dx)/5(sqrt(2)+x^5) multiplied both top and bottom.
OpenStudy (anonymous):
1/5 5x^5/5 / 2x^5/4 + c, is that correct?
OpenStudy (experimentx):
no ... you did not integrate
your answer will be
1/5 ln ( sqrt(2) + x^5) + C <--- try checking on wolfram.
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OpenStudy (anonymous):
whats the answer though ?
OpenStudy (mimi_x3):
Well, what do you need help with?
Looks, like someone answered it..
OpenStudy (anonymous):
i still dont know the answer!
OpenStudy (mimi_x3):
The link gives you the answer..
or you don't know how to do it?
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OpenStudy (anonymous):
oh thanks!
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