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OpenStudy (anonymous):
Which graph represents a phase shift of pi/2 units right for the graph of y=sinx?
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OpenStudy (anonymous):
You have no pictures of graphs
OpenStudy (inkyvoyd):
that would be -cos(x)
OpenStudy (anonymous):
y=sin(x-pi/2)
y=secx
cscx
cosx
OpenStudy (inkyvoyd):
Well.
OpenStudy (inkyvoyd):
Since you obviously can't do trig identities, let's have some fun!
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OpenStudy (inkyvoyd):
sin(-x)=-sin(x)
OpenStudy (inkyvoyd):
sin(x+y)=sinxcosy+sinycosx
OpenStudy (inkyvoyd):
Now, x=x, -pi/2=y
OpenStudy (inkyvoyd):
also, cos(-x)=cos(x)
OpenStudy (inkyvoyd):
ok.
sin(x-pi/2)
sin(x-90) -> convert to degrees because i'm a noob
sin(x-90)=sinxcos(-90)+sin(-90)cos(x)
=sinx*0-1*cos(x)
=-cos(x)
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OpenStudy (inkyvoyd):
Did you see what I did there? I gave youthe answer, and showed you why my answer was the same.
OpenStudy (anonymous):
thank u so much!!!
OpenStudy (inkyvoyd):
But, in general, a phase shift in a graph is represented by sin(x-theta), or cos(x-theta).
OpenStudy (anonymous):
Which of the following is a sinusoid?
a) y= [x]
b) y = 3 sqr x
c) x^2 + y^2 = 1
d) y=cosx
OpenStudy (anonymous):
The answer to the second question was D.
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