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x squared -1 over 1-x , I'm suppose to simplify but I dont see how, please help me understand
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\[x^2-1/1-x\] I'm going to assume this is the equation you are asking about. So what you do is you factor the top polynomial. \[x^2-1=(x+1)(x-1)\] Thus, you have (x+1)(x−1)/(1-x)
\[\LARGE x^2-\frac{1}{1-x}\] this ? or like post above :)
But you can rewrite x-1 as -(1-x) so you have...
i did the first one you posted
-(x+1)(1-x)/1−x=-(x+1) so your final answer is -x-1
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|dw:1334897105038:dw| is what i did
Im sorry i stil dont see how you got -x-1 from that
Okay so \[(x^2-1)/(1-x)=(x+1)(x-1)/(1-x)=-(x+1)(1-x)/(1-x)\]
You cancel out (1-x) then you are left with -(x+1)=-x-1
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